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3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
Yes, provided p = perimeter, b= breadth and h = height.
It is: 11h
Carbonic acid, H2CO3