This is a pretty straitforward algebra problem. 2x2 - 5 = 93 Add five to both sides of the equation. 2x2 = 98 Divide both sides by two. x2 = 49 Take the square root of both sides. SQRT(x2) = SQRT(49)
x = +/- 7 Note that the square root of 49 has two solutions: +7 and -7, because 72 = (-7)2 = 49.
square root of 8
If x squared -10 = 0 then x = the square root of 10
sqrt(4a2) = 21plus or minus (2a) = 21plus or minus (a) = 10.5a = +10.5a = -10.5
Yes and x = 2+square root of 6 or x = 2-square root of 6
2
4 squared minus 2 squared equals 12
square root of 8
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
If x squared -10 = 0 then x = the square root of 10
sqrt(4a2) = 21plus or minus (2a) = 21plus or minus (a) = 10.5a = +10.5a = -10.5
Yes and x = 2+square root of 6 or x = 2-square root of 6
x equals negative b plus or minus the square root of b squared minus 4bc over 2a
2
The square root of 28 minus the squared root of 7 =±2.64575131
It is: 9-4 = 5
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
All the time