3x2-9x = 0
x(3x-9) = 0
x = 0 or x = 3
9x2-9x-10 = (3x+2)(3x-5) when factored
3
9x^2 + 2^2 = 0 3x +2 = 0 therefore: x=-2/3
Assuming you mean 3x - 2 = 9x - 5...3x - 2 = 9x - 53x + 3 = 9x3 = 6x0.5 = x
You can solve this as a quadratic (it's degree is 2). 9x^2+2x=7 9x^2+2x-7=0 (Hey, a quadratic!) (9x-7)(x+1)=0 Thus, the solutions for x to this problem are -1, and 7/9.
x = -3
That factors to 3x(3x - 1)
9x2-9x-10 = (3x+2)(3x-5) when factored
8 - 3x = 9x - 10 +3x +3x______________8 = 12x - 10+10 +10______________18 = 12x__ ___12 123/2 = x, or x = 1.5
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
3
(3x-4)(3x+4)
9x^2 + 2^2 = 0 3x +2 = 0 therefore: x=-2/3
(3x + 8)(3x - 8)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
Assuming you mean 3x - 2 = 9x - 5...3x - 2 = 9x - 53x + 3 = 9x3 = 6x0.5 = x
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)