Q: How do you factor 9x squared minus 64?

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It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

That factors to 3x(3x - 1)

(3x-4)(3x+4)

This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)

Related questions

x2-9x can be factored by taking x out of each term x(x-9)

(9x + 8)(9x - 8)

It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

(x + 3)(3x - 2)

x2-9x+8=0 has two solutions:x = 8x = 1

(x + 12)(x - 3)

9x2-9x-10 = (3x+2)(3x-5) when factored

(x + 2)(3x - 1)(3x + 1)

9x2 - 18x + 99(x2 - 2x + 1)==========

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

x2 - 9x + 20 = (x - 4)( x - 5)