(3x + 8)(3x - 8)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
That factors to 3x(3x - 1)
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
(3x-4)(3x+4)
x2-9x can be factored by taking x out of each term x(x-9)
(9x + 8)(9x - 8)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
x2-9x+8=0 has two solutions:x = 8x = 1
(x + 12)(x - 3)
9x2-9x-10 = (3x+2)(3x-5) when factored
(x + 2)(3x - 1)(3x + 1)
9x2 - 18x + 99(x2 - 2x + 1)==========
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
x2 - 9x + 20 = (x - 4)( x - 5)