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given is that
4x+3y=6(3x+3y)=7
i.e., 6(3x+3y)=7 &&& 4x+3y=7 ---------------(1)
3x+3y=7/6
x+y=7/18 _________(2)
multiply eqn(2) by 4
4x+4y=28/18 -------------------------(3)
(3)-(1)
4x+3y-4x-4y=7-(28/18)
y= -98/18
substitute y in eqn(2)
x-98/18=7/18
x=7/18+98/18
x=105/18.
therefore x=105/18 : y= -98/18
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