You cannot solve it with two unknown values 'x' & 'y' .
However, it can be rearranged to form a strasight line eq'n.
Hence
-3x -3y = -15
Cancel down by '3'
Hence
-x -y = -5
Multiply by '-1',
Hence
x + y = 5
Hence
y = -x + 5 Is the straight line eq'n.
It has a slope/gradient of '-1' ; the coefficient of 'x'
It intercepts the y-axis at '5'. ; ( 0,5)
y=±√15
8x = 2x + 15 6x = 15 x = 15/6 = 2.5
If: 20x+5y = 15 Then: y = -4x+3
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
I'm an orange!
y=±√15
2y = 15 y = 15/2 y = 7.5
-9
x=15
16
-0.5
n - 15 = 86n = 86 + 15n = 101
Y=15/(2c+2x)
Divide each side by -15 and x = - 6/15.
-3
8x = 2x + 15 6x = 15 x = 15/6 = 2.5
-21 = 9a - 15 - 3a -6 = 6a -1 = a