You cannot solve it with two unknown values 'x' & 'y' .
However, it can be rearranged to form a strasight line eq'n.
Hence
-3x -3y = -15
Cancel down by '3'
Hence
-x -y = -5
Multiply by '-1',
Hence
x + y = 5
Hence
y = -x + 5 Is the straight line eq'n.
It has a slope/gradient of '-1' ; the coefficient of 'x'
It intercepts the y-axis at '5'. ; ( 0,5)
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y=±√15
8x = 2x + 15 6x = 15 x = 15/6 = 2.5
If: 20x+5y = 15 Then: y = -4x+3
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
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