x = -4 and y = -4.
These are known as simultaneous equations. We have to manipulate the equations in order to remove one of the variables. Then we can solve for the remaining variable. Once we have done this, we can substitute this value back into one of the original equations to solve for the other variable. So:
1. 6x - 2y = -16
2. 4x + 4y = -32
If we multiply 1. by 2 then we will end up with a -4y in one equation and 4y in the other. We will then be able to add these together which will cancel out and remove the y variable altogether.
So, 1. multiplied by 2 gives:
3. 12x - 4y = -32
Adding 2. & 3. gives:
4. 16x = -64
x = -64/16
x = -4
Now we have worked out the value of x we can substitute this value back into one of the original equations.
Substituting x = -4 back into 1. gives:
(6 * -4) - 2y = -16
-24 - 2y = -16
2y = -24 + 16
2y = -8
y = -4
We can double check we have solved this correctly by substituting both values into the other original equation.
Substituting x = -4 & y = -4 into 2. gives:
(4 * -4) + (4 * -4) = -32
-16 + -16 = -32
-32 = -32 (Yes this works, we have found the correct values of x & y!)
x = -8
20
h=16
y=16 x= -4
Solve using the quadratic formula
16 = 7f + 2 14 = 7f 2 = f
-12=m+4 -16=m
16
7x+2-2=16-27x = 147x/7 = 14/7x = 2
12y - 4 = 7y + 165y = 20y = 4
Equals anything... x is a variable. If that equation was set equal to zero then you could solve for x, but that is not what you have asked.
It equals postive 16 for more of these prombles go to uglymath.com thank you you ask it I solve it :p