2x + 1 = 1x + 11
Subtract 1x from each side:
1x + 1 = 11
Subtract 1 from each side:
1x = 10
First add coefficients: * 1x + 1x = 2x Second add the other values: * 4 + 5 = 9 Put it all together!: * 1x + 1x + 4 + 5 = 2x +9 * 2x + 9
There is always a 1 in front of the x but the 1 is invisible so it same as 1x + 1x = 2x x + x = 2x
It is a linear equation in one variable, x. Oh, I suppose you want the solution? 2x + 33 = 4x + 11 Subtract 2x from both sides: 33 = 2x +11 Subtract 11 from both sides: 22 = 2x Divide both sides by 2: 11 = x
2x+3x = 5x
If 5 x equals 9 plus 2x then x equals?
3x
If: x+1+2x = 1x+5 Then: x = 2
2x+2=x+6 first subtract 2x. -2x -2x2=-1x+6 then subtract 6-6 -6-4=-1x finally divide by -1x=4 X equals four.
x + 3 + 2x = x + 9 x + 2x + 3 = x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 1x - 1x + 2x + 3 = 1x - 1x + 9 2x + 3 = 9 2x + 3 - 3 = 9 - 3 2x + 3 - 3 = 9 - 3 2x = 9 -3 2x = 6 2x/2 = 6/2 2x/2 = 6/2 x = 6/2 x = 3
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
2x-11
How do you add 2x plus 3y equals 18 in 5x-y equals 11
x + 6 = 2x - 9 Add 9 to both sides: x + 15 = 2x Subtract 1x from both sides: 15 = 1x or 15 = x
First add coefficients: * 1x + 1x = 2x Second add the other values: * 4 + 5 = 9 Put it all together!: * 1x + 1x + 4 + 5 = 2x +9 * 2x + 9
2x+5=11 2x=6 x=3