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The angle is sin-1(7/9) = 51.05755873 or about 51 degrees

Alternatively using Pythagoras' theorem the smaller side is 4*sq rt of 2

So angle tan-1(7/4*sq rt of 2) = 51.05755873 or about 51 degrees

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Q: How do you solve for the angle of a right triangle The hypotenuse is nine and the opposite side is 7 I need to find the angle closest to the 90 degree angle Dont just put SOHCAHTOA please explain it?
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Related questions

How can you solve for angle A when only side a and side b of a right triangle are given in trigonometric functions?

It depends on the relationship of the sides to the angle. Assuming that neither side a or side b are the hypotenuse (longest side of the right triangle) and that side A is opposite the angle A and side b is closest (adjacent) to angle A then side a over side b will give the tangent of the angle A. If either side a or side b is the hypotenuse then when multiplied together their relationship to the angle A will give either the Sine or the Cosine of the angle A. Tangent = Opposite side / Adjacent side. Sine = Opposite / Hypotenuse. Cosine = Adjacent / Hypotenuse. A full explanation with diagram is at the related link below:


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SOH CAH TOA is a way of remembering what the functions sin, cos, & tan mean in a right angle triangle. With a triangle with one of the acute angles labelled (theta) the longest side H (Hypotenuse), the side opposite the labelled angle O, and the short side closest to the angle A (Adjacent) SOH ->SIN(Theta)=0/H CAH ->COS(Theta)=A/H TOA ->TAN(Theta)=O/A


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