Equals sin x divided by cos x. In a right-angled triangle it is the ratio of the two shorter sides, the one opposite the angle called x, divided by the the side closest to x.
sec(x)tan(x)
Tan(90) is an infinitely large number, and unresolved.
22
tan(3x)=1 3x= PI/4 x=PI/12 is the smallest positive number
tan(x)*csc(x) = sec(x)
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
x = tan-1(5) = 78.69 degrees
Tan(90) is an infinitely large number, and unresolved.
When x = 3.806663, tan(e^x) = 1.
sec(x)tan(x)
tan0.15
It is NOT equal. Try calculating tan x, and tan 6x, for a few values of "x", on your scientific calculator. Perhaps you are supposed to solve an equation, and see FOR WHAT values of "x" the two are equal?
You can't. tan x = sin x/cos x So sin x tan x = sin x (sin x/cos x) = sin^2 x/cos x.
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
x = tan(phi)
This would be a real bear to prove, mainly because it's not true.
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).