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logx(3) = log10(7)
(assumed the common logarithm (base 10) for "log7")
x^(logx(3)) = x^(log10(7))
3 = x^(log10(7))
log10(3) = log10(x^(log10(7)))
log10(3) = log10(7)log10(x)
(log10(3)/log10(7)) = log10(x)
10^(log10(3)/log10(7)) = x
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What is the log base 7 of 117?
log7(117) = 2.447273291
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve logx minus 3 plus log 4 equals log x?
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
How do you solve one half log sub 7 x equals log sub 7 20 minus 2 parenthesis log sub 7 2 plus log sub 7 5 parenthesis?
When solving this problem:1/2log7x = log720 - 2(log72 + log75)There are two things to note:lognx + logny = logn(xy)a(lognx) = lognxaUsing those two rules, we can simplify the given expression:1/2log7x = log720 - 2(log72 + log75)log7x1/2 = log720 - 2(log710)log7x1/2 = log720 - log7102log7x1/2 = log720 - log7100log7x1/2 = log7(1/5)√x = 1/5x = 1/25
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
2log 4y equals log 7 343 - log 5 25?
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
What is the log base 7 of 117?
log7(117) = 2.447273291
What is log7 plus logx equals 2 is?
We must assume that the question is asking us to determine the value of 'x'.log(7) + log(x) = 2log(7x) = 27x = 102 = 100x = 100/7 = 14.2857 (rounded)
How do you solve 3 log of 8 equals x?
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
How do you solve for x.log10x equals 4?
log(10x) = 410x = 104x = 103 = 1,000
How do you solve a log?
You calculate a log, you do not solve a log!
How do you solve 5.167 equals log Kf How to find the value of Kf?
If log(Kf) = 5.167 then Kf = 105.167 = 146,983 (approx).
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve logx minus 3 plus log 4 equals log x?
Use the identity log(ab) = log a + log b to combine the logarithms on the left side into a single term. Then take antilogarithms (just take the log away) on both sides.
How do you solve 2logx plus 3logx equals 10?
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
Solve for x log 9 x equals 2?
log9(x)=2 x=9^2 x=81
How would you solve 250 to the x power equals 400000?
250x = 400000 then x log 250 = log 400000 so x = log 400000 / log 250 Natural logs could have been used instead of logs to base 10.
