k=log4 91.8
4^k=91.8 -- b/c of log rules--
log 4^k=log 91.8 -- b/c of log rules--
k*log 4=log91.8 --> divide by log 4
k=log 91.8/log 4
k= 3.260
a = F divided by km
16
As x ∝ yz2 then x = kyz2 where k is a constant. Substituting the given figures, 40 = k*20*22 = 80k Then k = ½ and the formula is, x = ½yz2 So, x = ½ * 30 *32 = 135
The question is not clear. But if you want this in the form y=kx, then k must be 1.5
If y and x are related inversely, then the equation for y can be said to be:y = k/xTo find the constant k, substitute 12 for y and 6 for x (a pair of values that are known to satisfy the equation).y = k/x12 = k/612 X 6 = k72 = kThe value of the variation constant k is 72.
k equals 5.6
k = 129
k = pv/t. It is not possible to solve further with the information available.
79 + k = 84 84 - 79 = k k = 5
a = F divided by km
To do this, simply solve the multiplication problem:5.4 x 6.007 = k32.4378 = k
-108
X2 = k Take square root each side. X = (+/-) sqrt(k) ============
32
We cannot answer since you didn't give any numbers at all to solve this with.
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