tan(sec-1(5/2))
Start with sec-1(5/2), which is the same as cos-1(2/5). So there is a right triangle, where the side adjacent the angle is 2, and the hypotenuse is 5. Solve for the opposite side: sqrt(5² - 2²) = sqrt(21).
Tangent is opposite over adjacent, so the answer is sqrt(21)/2
Oh, what a happy little math question we have here! To solve arcsin(2/3), you simply take the inverse sine of 2/3, which is approximately 41.81 degrees. Remember, math is just like painting - take it one step at a time and enjoy the process of finding the answer.
2
Parenthesis
You expand the parenthesis out first. Then simplify the rest.
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
Yes, and parenthesis are the first thing you solve.
You are given: G(x) = x2 + x So if you want to solve G(2), all you need to do is replace all occurrences of "x" with the number 2, then work out what it comes to. G(2) = 22 + 2 ∴G(2) = 4 + 2 ∴G(2) = 6
Let y = sin(cos-1(2/5)) Suppose x = cos-1(2/5): that is, cos(x) = 2/5 then sin2(x) = 1 - cos2(x) = 1 - 4/25 = 21/25 so that sin(x) = sqrt(21)/5 which gives x = sin-1[sqrt(21)/5] Then y = sin(cos-1(2/5)) = sin(x) : since x = cos-1(2/5) =sin{sin-1[sqrt(21)/5]} = sqrt(21)/5 There will be other solutions that are cyclically related to this one but no range has been given for the solutions.
I presume that sin-1x is being used to represent the inverse sin function (I prefer arcsin x to avoid possible confusion). Make use of the trignometirc relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - sin2θ)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - sin2(arcsin(x))/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(2/3)) = √(1 - (2/3)2)/(2/3) = √(9/32 - 4/32) ÷ 2/3 = √(9 - 4) x 1/3 x 3/2 = 1/2 x √5
Parentheses is when you are doing an equation, and you solve the problem.
7a=2(-10)........................................answer is 20/7
You square the number in the parentheses.