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How do you solve tan parenthesis sec to the negative 1 parenthesis 5 over 2 closed parenthesis and another closed parenthesis?
Kiwi215
tan(sec-1(5/2))
Start with sec-1(5/2), which is the same as cos-1(2/5). So there is a right triangle, where the side adjacent the angle is 2, and the hypotenuse is 5. Solve for the opposite side: sqrt(5² - 2²) = sqrt(21).
Tangent is opposite over adjacent, so the answer is sqrt(21)/2
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∙ 12y ago
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