Oh, what a happy little math question we have here! To solve arcsin(2/3), you simply take the inverse sine of 2/3, which is approximately 41.81 degrees. Remember, math is just like painting - take it one step at a time and enjoy the process of finding the answer.
Dance on the table with one eye closed
just use the PEMDAS system. p-parenthesis e-exponents m-multiplication d-division a-adding s-subtracting
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
Order of operations: PEMDAS P-everythin inside the parenthesis E-all Exponents M-all multiplication D-all division A-all addition S-subtraction
That will depend on exactly how the equation is formed. In many cases, you can apply the inverse function to the outside first. Here is an example:sin(ln(x)) = ... To solve for "x", FIRST apply the inverse function of the sine (i.e., arcsin) to both sides of the equation. Next, apply the inverse of the natural logarithm to both sides. In this case, the exponential function (raise "e" to the power of the entire expression on both sides).
I presume that sin-1x is being used to represent the inverse sin function (I prefer arcsin x to avoid possible confusion). Make use of the trignometirc relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - sin2θ)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - sin2(arcsin(x))/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(2/3)) = √(1 - (2/3)2)/(2/3) = √(9/32 - 4/32) ÷ 2/3 = √(9 - 4) x 1/3 x 3/2 = 1/2 x √5
The inverse sin function I write as arcsin x. Make use of the trignometric relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - (sinθ)2)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - (sin(arcsin(x))2)/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(4/7)) = √(1 - (4/7)2)/(4/7) = √(49/72 - 16/72) ÷ 4/7 = √(49 - 16) x 1/7 x 7/4 = 1/4 x √33
tan(sec-1(5/2))Start with sec-1(5/2), which is the same as cos-1(2/5). So there is a right triangle, where the side adjacent the angle is 2, and the hypotenuse is 5. Solve for the opposite side: sqrt(5² - 2²) = sqrt(21).Tangent is opposite over adjacent, so the answer is sqrt(21)/2
Parenthesis
You expand the parenthesis out first. Then simplify the rest.
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
Yes, and parenthesis are the first thing you solve.
Parentheses is when you are doing an equation, and you solve the problem.
7a=2(-10)........................................answer is 20/7
You square the number in the parentheses.
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
No