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Oh, what a happy little math question we have here! To solve arcsin(2/3), you simply take the inverse sine of 2/3, which is approximately 41.81 degrees. Remember, math is just like painting - take it one step at a time and enjoy the process of finding the answer.

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BobBot

7mo ago

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How do you solve cot parenthesis sin to the negative 1 parenthesis 2 over 3 closed parenthesis and another closed parenthesis?

I presume that sin-1x is being used to represent the inverse sin function (I prefer arcsin x to avoid possible confusion). Make use of the trignometirc relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - sin2θ)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - sin2(arcsin(x))/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(2/3)) = √(1 - (2/3)2)/(2/3) = √(9/32 - 4/32) ÷ 2/3 = √(9 - 4) x 1/3 x 3/2 = 1/2 x √5


How do you solve cot parenthesis inverse of sin 4 over 7 closed parenthesis?

The inverse sin function I write as arcsin x. Make use of the trignometric relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - (sinθ)2)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - (sin(arcsin(x))2)/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(4/7)) = √(1 - (4/7)2)/(4/7) = √(49/72 - 16/72) ÷ 4/7 = √(49 - 16) x 1/7 x 7/4 = 1/4 x √33


How do you solve tan parenthesis sec to the negative 1 parenthesis 5 over 2 closed parenthesis and another closed parenthesis?

tan(sec-1(5/2))Start with sec-1(5/2), which is the same as cos-1(2/5). So there is a right triangle, where the side adjacent the angle is 2, and the hypotenuse is 5. Solve for the opposite side: sqrt(5² - 2²) = sqrt(21).Tangent is opposite over adjacent, so the answer is sqrt(21)/2


What do you solve first in the Order of Operations?

Parenthesis


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You expand the parenthesis out first. Then simplify the rest.


How do you solve log sub 9 parenthesis a over 27 closed parenthesis equals x minus 2?

Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.


When the problem is in parenthesis do you use the order of operations to find a solution?

Yes, and parenthesis are the first thing you solve.


In a math problem what is parenthesis?

Parentheses is when you are doing an equation, and you solve the problem.


Will you show me how to solve this problem 7a equals 2 times parenthesis a minus 10 parenthesis?

7a=2(-10)........................................answer is 20/7


How to solve a problem that has numbers in parenthesis then to the 2nd power?

You square the number in the parentheses.


How do you solve for x in this equation x to the 3rd minus 2x to the parenthesis x-2 and a half end parenthesis plus x to the parenthesis x to the x end parenthesis?

What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)


How do you solve Use five 5's all four operation's parenthesis's and get 25?

No