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How do you solve the simultaneous equations of x over 3 minus y over 4 equals 0 and x over 2 plus 3y over 10 equals 27 over 5 by the elimination method?
Wiki User
∙ 13y ago
x/3-y/4 = 0 => multiply all terms by 12 => 4x-3y = 0
x/2+3y/10 = 27/5 => multiply all terms by 10 => 5x+3y = 54
4x-3y = 0
5x+3y = 54
Add both equations together which will eliminate 3y:
9x = 54
Divide both sides by 9:
x = 6
Substituting the value of x into 5x+3y = 54 and 4x-3y = 0 gives y a value of 8.
Therefore: x = 6 and y = 8
Wiki User
∙ 13y ago
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