The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
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3x+4=10 To solve: 3x+4=10 3x=6 x=2
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
x + 4y = -14 eqn12x + 3y = 13 eqn2Using the elimination method we multiply eqn1 by 22x + 8y = -28 eqn1bSubtract eqn2 from eqn1b2x + 8y = -28 eqn1b2x + 3y = 13 eqn25y =-41y = -8 and 1/5substituting this into eqn1 we getx +4 (-41/5) = -14x = (14*5) / (41 *4)x = (35/82)
y=7+x =x=7-x
Add 4x - 2 to each side: 5x = 5 x = 1