3x+4=10 To solve: 3x+4=10 3x=6 x=2
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
x + 4y = -14 eqn12x + 3y = 13 eqn2Using the elimination method we multiply eqn1 by 22x + 8y = -28 eqn1bSubtract eqn2 from eqn1b2x + 8y = -28 eqn1b2x + 3y = 13 eqn25y =-41y = -8 and 1/5substituting this into eqn1 we getx +4 (-41/5) = -14x = (14*5) / (41 *4)x = (35/82)
y=7+x =x=7-x
Add 4x - 2 to each side: 5x = 5 x = 1
By elimination: x = 3 and y = 0
y=16 x= -4
(2,-2)
16
You cannot solve one linear equation in two variables. You need two equations that are independent.
Yes and it works out that x = 3 and y = 4
The answer is that it cannot be done. To solve a set of equations in k variables (in this case, 2) you need at least two independent equations.
x=8
467
How do you solve 4y plus x equals 8
n = 28
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.