With great difficulty because without an equality sign the given terms can't be considered to be an equation.
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
The centre is (-5, 3)
Solve the following equation for A : 2A/3 = 8 + 4A
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
(x-3)(x-2)
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
You cannot solve one linear equation with two variables.
There are two expressions in the question but no equation - so nothing to solve.
The question contains an expression but not an equation. You cannot solve an expression.
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
There is no equation (nor inequality) in the question. There is also no unknown variable. So there is nothing to solve.