With great difficulty because without an equality sign the given terms can't be considered to be an equation.
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5
The centre is (-5, 3)
Solve the following equation for A : 2A/3 = 8 + 4A
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
(x-3)(x-2)
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
You cannot solve one linear equation with two variables.
There are two expressions in the question but no equation - so nothing to solve.
Do you mean: 3x2+x-14 = 0 If so the solutions are: x = 2 and x = -7/3 using the quadratic equation formula
The question contains an expression but not an equation. You cannot solve an expression.
There is no equation (nor inequality) in the question. There is also no unknown variable. So there is nothing to solve.