-2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
-2x + 3x = -4 By combining like terms we get: x = -4.
is a quadratic equation for y, in terms of x.
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}
x = 2
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
-2x + 3x = -4 By combining like terms we get: x = -4.
x=-11
is a quadratic equation for y, in terms of x.
1 and 2
-3/2
The discriminant is -11.