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Q: How do you solve x equals 0 inequality?

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Since it is an inequality, there is no way to solve for x. It equals all real numbers.

10x=x 9x=0 x=0

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

x=2

x: x2 - 81 = 0

X = 1.8

9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0

x = 12

The above is not an inequality as stated.

x>-9

x=-.25.

2x(3x+6) = 0 x = 0 or x = -2

5 ^x = 0 5 = root square 0 5=0

4x2+50x = 0 4x(x+12.5) = 0 x = 0 or x = -12.5

3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3

144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144

Solve this problem -x squared -40x- 80 =0

Solve using the quadratic formula

"x squared equals to 25" is not an inequality! You need to re-think the question!

x2 + 7x = 0 => x*(x + 7) = 0 => x = 0 or x + 7 = 0 so that x = 0 or x = -7

solve for y so if x + y = 0 then y = -x

If x squared -10 = 0 then x = the square root of 10

5x2-2x = 0 x(5x-2) = 0 Therefore: x = 0 or x = 2/5

16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}

5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3