9x2-9x = 0
x2-x = 0
x(x-1) = 0
x = 1 or x = 0
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9x-53=6/x 9x2-53x=6 9x2-53x-6=0 9x2+x-54x-6=0 x(9x+1)-6(9x+1)=0 (9x+1)x(x-6)=0 9x+1=0 or x-6=0 9x=-1 or x=6 x=-1/9 or x=6
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3
Presumably this is a quadratic equation question in the form of: 9x2-12x+4 = 0 When factored: (3x-2)(3x-2) = 0 Solution: x = 2/3 and also x = 2/3 (they both have equal roots)
Solve this problem -x squared -40x- 80 =0