0
The problem is a quadratic.
Rewritten as x2-x+5=0
Since this cannot be factored, the quadratic formula can be used.
I can tell there will be imaginary numbers because the discriminant is < 0
b2-4ac = 1-4(1)(5) = -19
(1±(√12-4(1)(5)))/2(1) = confusing = 1/2 ± i√19
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