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You place X and Y on the same side to get a standard equation.

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Q: How do you turn a slope intercept equation into a standard equation?
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How do you turn equations into slope intercept form?

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How do you turn standard equations in slope intercept equations?

slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form


How do you turn 10y plus 4x equals plus 10 into slope intercept form?

It is: y = -0.4x+1 when in slope intercept form.


What is the slope of the graph of 3x plus y equals 7?

3x + y = 7 First, turn the equation into the slope-intercept form, y = mx + b, where m is the slope of the graph that that equation represents (solve for y).3x + y = 7 subtract 3x to both sidesy = -3x + 7So you clearly see that the slope is -3.


How do you turn 20x plus 80y equals 0 into slope intercept form?

If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept


How do you turn x-4y equals 11 in slope intercept form?

by just doing the problem


What is the y intercept of the line x-8y equals 4?

x - 8y = 4; turn the equation in the slope-intercept form, y = mx + b, where b is the y-intercept. x - 8y = 4x - x - 8y = -x + 4-8y = -x + 4 divide by -8 to both sidesy = x/8 - 1/2 Thus, the y-intercept is -1/2.


How would you turn 8x-5y equals -40 into slop intercept?

8x-5y = -40 -5y = -8x-40 y = 1.6x+8 which is now in slope intercept form


What is the slope and y intercept for the line y equals -2x plus 8?

Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn


How do you turn x plus y equals 90 into slope intercept form?

Subtract x from both sides:- y = -x +90


What is the equation of the perpendicular bisector of the line joining s 2s to 3s 8s?

(s, 2s) and (3s, 8s); s ≠ 0, otherwise we have just one point, the origin.First, find the slope of the non-vertical line joining the two given points.(2s - 8s)/(s - 3s) = -6s/-2s = 3The slope of the perpendicular line must be the negative reciprocal of 3. Therefore it is -1/3.Since the line is a perpendicular bisector, it must passes through the midpoint[(s +3s)/2, (2s + 8s)/2] = (2s, 5s).Since we know the slope and one point on the line, we can write the point-slope form of the equation,y - 5s = -(1/3)(x - 2s).If you want, you can turn the equation into the slope-intercept form or the standard form.Another Answer:-It is: x+3y-17s = 0 in its general form


How do your turn x plus y equals 4 into y intercept form?

If you are talking about slope/intercept form... you have to remember the formula: y=mx+b Therefore, if you have x+y=4, you need to subtract x from both sides of the equation. x-x+y=-x+4 ... then simplify y=-x+4 Remember that -x is the same as -1x