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How do you turn standard equations in slope intercept equations?
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
How would you turn 8x-5y equals -40 into slop intercept?
8x-5y = -40 -5y = -8x-40 y = 1.6x+8 which is now in slope intercept form
How do you turn a slope intercept equation into a standard equation?
You place X and Y on the same side to get a standard equation.
How do you turn 2x-4y equals 8 in slope intercept form?
2x-4y = 8 2x = 4y + 8 2x - 8 = 4y 2x/4 - 8/4 = y (1/2)x - 2 = y So, y = (1/2)x - 2, where 1/2 is the slope and -2 is the y-intercept :)
What is the slope and y intercept for the line y equals -2x plus 8?
Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn
How do you turn standard equations in slope intercept equations?
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
How do you turn 10y plus 4x equals plus 10 into slope intercept form?
It is: y = -0.4x+1 when in slope intercept form.
How do you turn x-4y equals 11 in slope intercept form?
by just doing the problem
How do you turn 20x plus 80y equals 0 into slope intercept form?
If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept
How would you turn 8x-5y equals -40 into slop intercept?
8x-5y = -40 -5y = -8x-40 y = 1.6x+8 which is now in slope intercept form
How do you turn x plus y equals 90 into slope intercept form?
Subtract x from both sides:- y = -x +90
How do you turn 3x-6y equals 12 in slope intercept form?
3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form
How do you turn 6x-3y-9 equals 0 into slope intercept form?
Slope intercept form is y=mx+b To convert 6x-3y-9=0 into this form, we must first isolate y. We do this by adding 3y to both sides. Now we have 3y=6x-9 To simplify this, we divide both sides by 3. The answer is now y=2x-3
How do you turn a slope intercept equation into a standard equation?
You place X and Y on the same side to get a standard equation.
How do you do graph with slope and y intercept form?
If you are looking at a graph with to coordinate The "Y-Intercept is" what is on the "Y-Axis". The "Y-Axis" is the big line that runs through the middle of your coordinate plain (your graph). The "X-Axis" is what goes through the the middle of your coordinate plain but runs side-to-side. Now, you must find the slope of your two points. A slope intercept form would look like this---> y = mx + b. "m" is your slope and "b" is your y-intercept. We need to turn what we have now into that. So our slope "m" would be -3/4, now you may ask how did I do that, I'll show you. You might wanna draw out your two points on the graph to understand this better. You look at lets say the (0,2) first... now the way to find the slope is rise/run. That means you look at your rise from that point to the other point then the run from that point to the other point, the rise is what goes up and down, and run is what goes side to side. (0,2) is 3 lines away from (4,1). Then when you go the first 3 lines down, which is your rise, then you go 4 lines over which is you run. When you do that, you should be at your other point. That means your slope is -3/4. So far your slope intercept form looks like this---> y = -3/4x + b. Now were almost done, the next part is easy. Now we just look at our "Y-Axis". (0,2) is on the "Y-Axis" already so our "Y-Intercept" is 2. if it was below the "Y-Axis" our "Y-Intercept" would be -2. That leaves our Slope Intercept form at y = -3/4x + 2. That is Your Slope-Intercept form of a Linear Equation.
How do you turn 2x-4y equals 8 in slope intercept form?
2x-4y = 8 2x = 4y + 8 2x - 8 = 4y 2x/4 - 8/4 = y (1/2)x - 2 = y So, y = (1/2)x - 2, where 1/2 is the slope and -2 is the y-intercept :)
What is the slope and y intercept for the line y equals -2x plus 8?
Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn
