slopeintercept equations are used to find the slope and intercept (obviously lol)
they are set up like this
y=mx+b
m is the slope and b is the y-intercept
lets say you have an equation like...
2x + y = 5 (now minus 2x from both sides)
2x - 2x + y = 5 - 2x (simplify)
y = 5 - 2x
just use algebra to turn the standard form to slope intercept form
Equation
You place X and Y on the same side to get a standard equation.
To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn
2x-4y = 8 2x = 4y + 8 2x - 8 = 4y 2x/4 - 8/4 = y (1/2)x - 2 = y So, y = (1/2)x - 2, where 1/2 is the slope and -2 is the y-intercept :)
Equation
You place X and Y on the same side to get a standard equation.
It is: y = -0.4x+1 when in slope intercept form.
If: 20x+80y = 0 Then: 80y = -20x And: y = -0.25x So the slope is -0.25 and it has no y intercept
by just doing the problem
To convert the equation 8x - 5y = -40 into slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, you need to solve for y. First, isolate y by subtracting 8x from both sides to get -5y = -8x - 40. Then, divide by -5 to get y = 8/5x + 8, which is the slope-intercept form of the equation. The slope is 8/5 and the y-intercept is 8.
Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn
Subtract x from both sides:- y = -x +90
3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form
2x-4y = 8 2x = 4y + 8 2x - 8 = 4y 2x/4 - 8/4 = y (1/2)x - 2 = y So, y = (1/2)x - 2, where 1/2 is the slope and -2 is the y-intercept :)
3x + y = 7 First, turn the equation into the slope-intercept form, y = mx + b, where m is the slope of the graph that that equation represents (solve for y).3x + y = 7 subtract 3x to both sidesy = -3x + 7So you clearly see that the slope is -3.
If you are looking at a graph with to coordinate The "Y-Intercept is" what is on the "Y-Axis". The "Y-Axis" is the big line that runs through the middle of your coordinate plain (your graph). The "X-Axis" is what goes through the the middle of your coordinate plain but runs side-to-side. Now, you must find the slope of your two points. A slope intercept form would look like this---> y = mx + b. "m" is your slope and "b" is your y-intercept. We need to turn what we have now into that. So our slope "m" would be -3/4, now you may ask how did I do that, I'll show you. You might wanna draw out your two points on the graph to understand this better. You look at lets say the (0,2) first... now the way to find the slope is rise/run. That means you look at your rise from that point to the other point then the run from that point to the other point, the rise is what goes up and down, and run is what goes side to side. (0,2) is 3 lines away from (4,1). Then when you go the first 3 lines down, which is your rise, then you go 4 lines over which is you run. When you do that, you should be at your other point. That means your slope is -3/4. So far your slope intercept form looks like this---> y = -3/4x + b. Now were almost done, the next part is easy. Now we just look at our "Y-Axis". (0,2) is on the "Y-Axis" already so our "Y-Intercept" is 2. if it was below the "Y-Axis" our "Y-Intercept" would be -2. That leaves our Slope Intercept form at y = -3/4x + 2. That is Your Slope-Intercept form of a Linear Equation.