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Q: Is 56 the product of 3 different prime numbers?

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56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56

no

As a product of its prime factors: 2*2*2*7 = 56

As a product of its prime factors in exponents: 26*56 = 1,000,000

The prime numbers (factors) of 56 are: 2 and 7

The prime numbers (factors) of 56 are: 2 and 7

56 = 2 x 2 x 2 x 7

56 = 2 x 2x 2 x 7 56 = 23 x 7

Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.

Yes it can be divided by 1,7 and 8

53 and 3 are two prime numbers that add up to 56

One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...

The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.

56 does not have only three prime factors.

56=2x2x2x7

56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.

As a product of its prime factors: 2*3*7 = 42 As a product of its prime factors: 2*2*2*7 = 56

None of those four numbers are prime numbers.

As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39

As a product of its prime factors: 2*2*2*2 = 16 As a product of its prime factors: 2*2*2*7 = 56

300

The product of the prime factors of a number is the number itself. 2 x 2 x 2 x 7 = 56

They are: 2*2*2*7 = 56

They are: 2+11+43 = 56