The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
The question cannot be answered without information regarding of what object and of what size.
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
The side of the square is 1/2 sqrt(2) feet = 8.485 inches. (rounded)
The size or length of a square is related to its area as the area of a rectangle s the product of the length times the width. As a square is a special type of rectangle, where the length is equal ti the width, the area of a square is the length times the length or length^2, also spoken as "length squared".
Using Pythagoras' theorem the diagonal works out as 51 inches
Draw a square which is 1 unit by 1 unit in size. By Pythagoras, the diagonal of the square will be sqrt(2) units in length.
Arthur Pythagoras: Diagonal = sqrt (square of side 1 + square of side 2) In your case D = sqrt (2 x 2500) = 70.71cm Addendum: If it is a square, as is your case, multiply the length of one side by the square root of 2: 1.4142 * 50.00 cm = 70.71 cm. (Arthur?)
The square's sides will be the sqrt 2 = about 1.414 inches.(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)diagonal = (sq rt 2) x sidediameter = sq rt (s^2 + s^2).2 inches = sq rt (2 s^2)2 inches - (sq rt 2) x s2 inches = 1.414 sand s = 1.414
13 cm Solved with the help of the quadratic formula and Pythagoras' theorem.
d = 11.5 inches.
The question cannot be answered without information regarding of what object and of what size.
screen size of any computer or tv screen is measured along the diagonal. so screen size 14 inches means that the length of the diagonal of the screen is 14 inches
A square whose diagonal is the diameter of the circle. So, if it is a circle with diameter 18 units then the diagonal of the square is 18 units and so its side is 9*sqrt(2) = 12.7 units.
length2+width2 = diagonal2 and the square root of this is the size of the diagonal
The side of the square is 1/2 sqrt(2) feet = 8.485 inches. (rounded)
Given side S, the diagonal is S * √2. So the difference is Diagonal - side = (S √2) - S = S (√2 - 1) so Given Difference / (2 - 1) = S That's the size of the side of the square :)