Area of a square = (length of one side)2
49 cm2 = (length of one side)2
7 cm = length of one side
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Perimeter of a square = distance all the way around it
Perimeter = (4) x (length of one side)
Perimeter = (4) x (7 cm) = 28 cm
It is different for each shape. A perimeter is the distance around an object and the area is the square units it takes up.
To find the perimeter of a square, you first need to work out the side length. The area of a square is L2 where L is the side length. The area of the square in the question is 16cm2 so L is the square root of 16, or 4. To get the perimeter of the square, we simply multiply the side length by 4. In this case 4x4=16, so the perimeter of the square is 16cm.
The dimensions work out as 7 units and 15 units
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.
It is different for each shape. A perimeter is the distance around an object and the area is the square units it takes up.
To find the perimeter of a square, you first need to work out the side length. The area of a square is L2 where L is the side length. The area of the square in the question is 16cm2 so L is the square root of 16, or 4. To get the perimeter of the square, we simply multiply the side length by 4. In this case 4x4=16, so the perimeter of the square is 16cm.
The dimensions work out as 7 units and 15 units
Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
There is no one answer, it depends on the shape. The smallest value of perimeter will be for a circle. For a four sided shape the smallest will be for a square, for a rectangle the perimeter gets bigger the longer and narrower the area becomes. Knowing the area in acres gives the number of square yards only, you have to know either the length or width, work out the width or length as the case may be, then just add up the four sides.
Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.
Using Pythagoras' theorem and the quadratic equation formula they work out as:- Area: 309.3144 square cm Perimeter: 86.16 cm
Forget about the area and use Pythagoras' theorem: 62+82 = 100 and the square root of this is 10 New perimeter = 6+8+10 = 24 cm
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
With great difficultly. The area could be any value greater than 0 units2 and less than or equal to the area of a square with the given perimeter which would be 1/16 x perimeter2 units2. To know which of the possible areas you would need to know the length of one side, then you can work out the area: perimeter = 2 x (length + width) ⇒ width = (1/2 x perimeter) - length ⇒ area = length x width = length x ((1/2 x perimeter) - length) = (1/2 x perimeter x length) - length2
If the sides are in cm, then you would multiply the length of the shape by the width, which equals area. And area is in the unit of the sides but squared. So in this example it would be cm2. ========================================= The answer to the question is: You can't. The perimeter doesn't tell you what the area is. You can have two different drawings with the same perimeter and different areas, or with the same area and different perimeters. Even if they're both triangles, or both rectangles, etc. You can't take perimeter and 'work out' area from it.