2 x 2 x 2 x 2 x 31 = 496
496 has two prime factors, but no prime factor pair. 2 x 2 x 2 x 2 x 31 = 496
factors: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496prime factors: 2(4), 31Assuming that by "prime numbers of 496," you mean the prime factorization:24 * 31 or 2 * 2 * 2 * 2 * 31
It is: 24*31 = 496
NO
It is: 2*2*2*2*31 = 496
The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
The factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, 248, and 496.
The positive integer factors of 496 are:1, 2, 4, 8, 16, 31, 62, 124, 248, 496The factors of 496 are: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496.
The numbers are 31 and 32.
Find any factor - like 2, then divide by 2, to get the other factor: 2 x 248. Continue finding more factors for the number to the right, until you divided the number into prime factors.
The number 992 is a positive integer that can be divided by several other integers. If you divide 992 by 1, it remains 992. However, if you divide 992 by 2, you get 496, and dividing it by 4 results in 248. Additionally, 992 can be expressed as the product of its prime factors: 2^5 × 31.
8 multiplied by 62 is 496.