The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
49600%496= 496 * 100%= 49600%
496 = (4 x 100) + (9 x 10) + (6 x 1)
496 - 237 = 259
No - 496 is a perfect number.
It is: 2*2*2*2*31 = 496
factors: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496prime factors: 2(4), 31Assuming that by "prime numbers of 496," you mean the prime factorization:24 * 31 or 2 * 2 * 2 * 2 * 31
The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
4*4*31
NO
496 has two prime factors, but no prime factor pair. 2 x 2 x 2 x 2 x 31 = 496
49600%496= 496 * 100%= 49600%
2 x 2 x 2 x 2 x 31 = 496
496 = (4 x 100) + (9 x 10) + (6 x 1)
9 and 62
There is only one Perfect Number within this range : 496. If 2ⁿ - 1 is prime then 2ⁿ⁻¹(2ⁿ - 1) is a perfect number. In this instance n = 5 then, 2⁴(2⁵ - 1) = 16 x 31 = 496...........and 31 is a prime number.
496/1240 x 100 = 40 Therefore, 496 is 40 percent of 1240.