There is more than one possible answer. The prime factors of 16 are 2, 2, 2, and 2. It has four prime factors, but only one distinct prime factor. The prime factors of 24 are 2, 2, 2, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 36 are 2, 2, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 40 are 2, 2, 2, and 5. It has four prime factors, but only two distinct prime factors. The prime factors of 54 are 2, 3, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 56 are 2, 2, 2, and 7. It has four prime factors, but only two distinct prime factors. The prime factors of 60 are 2, 2, 3, and 5. It has four prime factors, but only three distinct prime factors. The prime factors of 81 are 3, 3, 3, and 3. It has four prime factors, but only one distinct prime factor. The prime factors of 84 are 2, 2, 3, and 7. It has four prime factors, but only three distinct prime factors. The prime factors of 88 are 2, 2, 2, and 11. It has four prime factors, but only two distinct prime factors. The prime factors of 90 are 2, 3, 3, and 5. It has four prime factors, but only three distinct prime factors.
The prime factors of 336 are: 2,3,7
The factors of 1993 are: 1 1993 The prime factors are: 1993 is a prime number.
The factors of 401 are: 1 401 The prime factors are: 401 is a prime number.
30 has three prime factors. The prime factors are 2,3,5.
496 has two prime factors, but no prime factor pair. 2 x 2 x 2 x 2 x 31 = 496
2 x 2 x 2 x 2 x 31 = 496
NO
It is: 24*31 = 496
The factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, 248, and 496.
The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
It is: 2*2*2*2*31 = 496
The positive integer factors of 496 are:1, 2, 4, 8, 16, 31, 62, 124, 248, 496The factors of 496 are: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496.
Find any factor - like 2, then divide by 2, to get the other factor: 2 x 248. Continue finding more factors for the number to the right, until you divided the number into prime factors.
1, 2, 4, 8, 16, 31, 62, 124, 248, 496
Prime factors are factors that are also prime numbers.
divide by 2 then divide every answer by 2 That will give you 496, 248, 124, 62 and 31. The other 4 are 2, 4, 8 and 16.