y=mx+b, right? So, b is the height of the y-intercept that you already have. M is the slope, rise over run. The slope is the same at all part of a line. You take the distance up from the y-intercept to the point and divide by the distance right from the y-intercept to the point. Replace m with that and you have the equation.
(0,-6) m=-2
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
Yes, I could, if I knew the slope of the line given.
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25
(0,-6) m=-2
You would need a point ex: (4,5) y=5 if its a horizontal line you just write y=(value of y on the given point)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
Yes, I could, if I knew the slope of the line given.
x = 1 (the line intersects the x-axis at 1, and is parallel to the y-axis)We cannot write the equation on the Slope-intercept form, since the slope of the line is undefined. 1 is the x-coordinate of any point on the given line.
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
Parallel straight line equations have the same slope but with different y intercepts