(0,-6) m=-2
Yes, I could, if I knew the slope of the line given.
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
The equation is x = -7.
Yes, I could, if I knew the slope of the line given.
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
Any equation parallel to the x-axis is of the form:y = constant In this case, you can figure out the constant from the given point.
p (2,-1) and slope 3
Parallel straight line equations have the same slope but with different y intercepts
8
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
sda