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Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
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How do you write an equation that is perpendicular?
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
Is a quadrilateral perpendicular?
It could be but does not have to be... (Perpendicular to what?)
What lines are perpendicular 2x 3?
y = -0.5x + c where c is any number. The equation could, of course, be written as x + 2y = k where k (=2c) is any number.
How many perpendicular sides does a pentagon have?
A regular pentagon has zero perpendicular sides. If it is irregular, it could have as many as 2 or 4 perpendicular sides.
Find an equation of the circles passing through the points A 1 2 and B 3 4 and tangent to the line 3x plus y equals 3?
The given information is not enough to write the equation of a circle. So we need to work a little bit.Plot A(1, 2) and B(3,4) in a rectangular coordinate system. Draw the tangent line, y = -3x + 3, which cuts the x-axis at (1, 0). By looking at the position of the points A, B, and at the path of the tangent line, think that the point where the tangent touches the circle could be (1, 0) or close to.Plan: The center of the circle is at the intersection point of the perpendicular line to tangent at the point of tangency, and the perpendicular bisector of the segment AB (reason: a tangent to a circle is perpendicular to its radius; the perpendicular bisector of a chord passes through the center).Solution:Let's suppose that (1, 0) is the point of tangency.Find the midpoint M of AB: M = ((1+3)/2, (2+4)/2) = (2, 3)Find the slope of the line that passes though A and B: m = (4-2)/3-1) = 1Find the equation of the perpendicular bisector of AB (whose slope must be -1 and passes through (2, 3)):y = -1x + b; let (x, y) = (2, 3)3 = -1*2 + bb = 5y = -x + 5Find the equation of the perpendicular line to the tangent (whose slope is 1/3 since the perpendicular lines have negative reciprocal slopes) and passes through (1, 0)):y = 1/3x + b; let (x, y) = (1, 0)0 = (1/3)*1 + bb = -1/3y = (1/3)x - 1/3Find the intersection point of y = -x + 5 and y = (1/3)x - 1/3-x + 5 = (1/3)x - 1/3(4/3)x = 16/3x = 16/3 * 3/4x = 4 implies y =1So the point (4, 1) could be the center of the circle.If we compute the distances between (4, 1) and (1, 0), (1, 2), (3,4), we see that they have the same length, √10, then we say the center of the circle is (4,1) and the radius has a length of √10.Thus, the equation of the circle that passes through (1, 2) and (3, 4) is the equation of a circle with center (4, 1) and a radius of √10.(x - 4)2 + (y - 1)2 = 10Let's solve the problem without risking extra work (we clearly see that our guess for the point of tangency was right).After we draw the given information on the rectangular system, we would like to draw a parallel line to the tangent line that passes through the point B(3, 4). For this we need the equation of the line to use its slope to draw it and to find the point of intersection with the perpendicular bisector of segment AB (since the center of the circle lies there; see above); (the slope is -3, since parallel line have the same slope).y = -3x + b; ; let (x, y) = (3, 4)4 = -3*3 + bb = 13y = -3x + 13Let's find the intersection point of y = -x + 5 and y = -3x + 13-x + 5 = -3x + 132x = 8x = 4 implies y = 1, say O(4, 1)Let's find the length of the congruent (O lies on the perpendicular bisector) segments OA and OB, maybe they are radii.OA = OB = √((4-1)2+(1-2)2) = √10.Since the point O lies in the same time on the perpendicular bisector of AB and on the parallel line to the tangent, let's find the equation of the perpendicular line to the tangent that passes through O (the slope is 1/3 since the perpendicular lines have negative reciprocal slopes):y = (1/3)x + b; let (x, y) = (4, 1)1 = (1/3)*4 + bb = -1/3y = (1/3)x - 1/3Let's find the intersection point of y = -3x + 3 and y = (1/3)x - 1/3 (maybe this would be the point of tangency):-3x + 3 = (1/3)x - 1/3(4/3)x = 4/3x = 1 implies y = 0; say T(1, 0)Let's find the length of OT:OT = √((4-1)2+(1-0)2) = √10.Since OA, OB, and OT have the same length, they are radii of the circle with center O(4, 1). So our guess was right
How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
What equation would be perpendicular to the equation y equals x plus 5?
It could be y = -x+5
What equation would be perpendicular to the equation y equals 1.5x plus 5?
It could be y = -2/3x+5
Which is the equation of a line that is perpendicular to the line represented by y equals three fourths x subtract one half?
If you mean: y = 3/4x-0.5 then the perpendicular equation could be y = -4/3x-5
How do you write an equation that is perpendicular?
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
Is a quadrilateral perpendicular?
It could be but does not have to be... (Perpendicular to what?)
What could cause Jet Fuel A MSEP ratings to degrade as the fuel passes through a pipeline system?
Contamination with a fuel containing surfactants could cause the MSEP rating to degrade as it passes through a pipeline. See also the links below.
Why is the human eye sensitive to the visible light?
That is because the visibile light is what passes easily through our atmosphere. It would not benefit us much if we could see certain other frequencies, that hardly pass through the atmosphere.That is because the visibile light is what passes easily through our atmosphere. It would not benefit us much if we could see certain other frequencies, that hardly pass through the atmosphere.That is because the visibile light is what passes easily through our atmosphere. It would not benefit us much if we could see certain other frequencies, that hardly pass through the atmosphere.That is because the visibile light is what passes easily through our atmosphere. It would not benefit us much if we could see certain other frequencies, that hardly pass through the atmosphere.
What lines are perpendicular 2x 3?
y = -0.5x + c where c is any number. The equation could, of course, be written as x + 2y = k where k (=2c) is any number.
What is the slope of a line perpendicular to a line with a slope of zero?
To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of a line that is perpendicular to a line with a slope of -2/3 is 3/2, (or 11/2 or 1.5).
Does a pentagon have perpendicular line?
yes they do. they have a perpendicular line. * * * * * No, a pentagon, as in a regular polygon does not have perpendicular lines. An irregular pentagon could, and you can always add perpendicular lines to any shape.
Which two-dimensional figure could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicular to its base and not through its vertex?
trapezoid
