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Start with 3 in the middle of the bottom row.

Put each succeeding number a knights move up ie 6 goes in top left, 9 in middle right.

When the target box is occupied, put the number immediately above its predecessor.

This will give you a grid as follows:

6 27 12

21 15 9

18 3 24

All lines total 45.

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Q: How do you write first 9 multiples of 3 in a grid form of 3x3 such that the sum of its vertical horizontal diagonal numbers is the same?
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