a
C Square
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
A is proportional to C4.
Suppose sqrt(A) = B ie the square with sides B has an area of A and its perimeter is 4*B. Now consider a rectangle with sides C and D whose area is A. So C*D = A = B*B so that D = B*B/C Perimeter of the rectangle = 2*(C+D) = 2*C + 2*D = 2*C +2*B*B/C Now consider (C-B)2 which, because it is a square, is always >= 0 ie C*C + B*B - 2*B*C >= 0 ie C*C + B*B >= 2*B*C Multiply both sides by 2/C (which is >0 so the inequality remains the same) 2*C + 2*B*B/C >= 4*B But, as shown above, the left hand side is perimeter of the rectangle, while the right hand side is the perimeter of the square.
You do a^2 x b^2 = c^2 where a=the base, b= the height and c=the diagonal.More info: take the square of "a" and the square of "b" and multiply them together, then take your answer and find the square root of it, that is "c" (the diagonal).
Here are the steps: ax^2 + bx + c = 0 Subtract c and divide by a x^2 + (b/a)x = -(c/a) Take the square of (b/a)/2 and add it to both sides (x + ((b/a)/2))^2 = -(c/a) + ((b/a)/2)^2 Take the square root of both sides Subtract ((b/a)/2) and you have your solutions: x = -(c/a) + ((b/a)/2)^2 - ((b/a)/2) x = (c/a) - ((b/a)/2)^2 - ((b/a)/2)
This question cannot be answered. You will have to give me the number to the square root. * * * * * a = ±sqrt(c^2 - b^2)
Let x be the parameter to be taken square root. a = 0 b = x loop: c = (a+b)/2 if c*c > x then b = c else a = c Repeat until accurate enough result is obtained in c or until c*c equals x.
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
Area measured in square units = 1/2*(sum of parallel sides)*height If a and b are parallel, and b>a ((a+b) sqrt((a-b+c-d) (a-b-c+d) (a-b+c+d) (-a+b+c+d)))/(4 (b-a))