it doesn't
Air resistance, Gravity, Friction, The attachment of the pendulum to the support bar, Length of String, Initial Energy (if you just let it go it will go slower than if you swing it) and the Latitude. Amplitude only affects large swings (in small swing the amplitude is doesn't affect the swing time). Mass of the pendulum does not affect the swing time. A formula for predicting the swing of a pendulum: T=2(pi)SQRT(L/g) T = time pi = 3.14... SQRT = square root L = Length g = gravity
It messes up the math. For large amplitude swings, the simple relation that the period of a pendulum is directly proportional to the square root of the length of the pendulum (only, assuming constant gravity) no longer holds. Specifically, the period increases with increasing amplitude.
The period of a pendulum is (sort of) independent of the amplitude. This is technically true for very small, "infinitesimal" swings. In this range, amplitude does not affect period. For larger swings, however, a circular error is introduced, but it is possible to compensate with various designs. See the Related Link below for further information.
The amplitude of a pendulum is the distance between its equilibrium point and the farthest point that it reaches during each oscillation.
The pendulum swings twice as far.
Air resistance, Gravity, Friction, The attachment of the pendulum to the support bar, Length of String, Initial Energy (if you just let it go it will go slower than if you swing it) and the Latitude. Amplitude only affects large swings (in small swing the amplitude is doesn't affect the swing time). Mass of the pendulum does not affect the swing time. A formula for predicting the swing of a pendulum: T=2(pi)SQRT(L/g) T = time pi = 3.14... SQRT = square root L = Length g = gravity
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
it doesnt affect the amplitude as the mass and length remain constant
no.
It messes up the math. For large amplitude swings, the simple relation that the period of a pendulum is directly proportional to the square root of the length of the pendulum (only, assuming constant gravity) no longer holds. Specifically, the period increases with increasing amplitude.
no it doesnt affect the period of pendulum. the formulea that we know for simple pendulum is T = 2pie root (L/g)
Galileo's pendulum experiment showed that the period of the swing is independent of the amplitude (size) of the swing. So the independent variable is the size of the swing, and the dependent variable is the period. The experiment showed there was no dependence, for small swings anyway. The experiment led to the use of the pendulum in clocks.
In an ideal pendulum, the only factors that affect the period of a pendulum are its length and the acceleration due to gravity. The latter, although often taken to be constant, can vary by as much as 5% between sites. In a real pendulum, the amplitude will also have an effect; but if the amplitude is relatively small, this can safely be ignored.
-- friction in the pivot -- air moving past the pendulum -- the effective length of the pendulum -- the local acceleration of gravity
Assuming an idealised pendulum with a small amplitude, both are examples of simple harmonic motion. That is, the second derivative of the curve is directly proportional to its displacement but in the opposite direction. If the amplitude (swing) of the pendulum is large or if the majority of its mass is not oi the "blob" the relationship is only approximate.
The period of a pendulum is (sort of) independent of the amplitude. This is technically true for very small, "infinitesimal" swings. In this range, amplitude does not affect period. For larger swings, however, a circular error is introduced, but it is possible to compensate with various designs. See the Related Link below for further information.
A heavier pendulum will swing longer due to its greater inertia.