First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
if 2y-x=4, than y=1/2*x+2 we can now see that the graph is linear with slope 1/2 and goes through point (0,2)
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
x+2y=4. choose random values for x, sub in to get y, and then plot as points in format (x,y) i.e. x=1, 1+2y=4, 2y=3, y=1.5, point 1,1.5 x=2, 2+2y=4, 2y=2, point 2,2. plot both. min of 2 points for a line
The inequality is: x+2y > 4
This means that 2y - 3 = 2y + 4 which is not possible.
Exactly (2y + 4) .
Infinite, both equations are equivalent and all possible solutions can be represented on the graph y = 4 - x
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
first get both your equations into standard form... x + 2y = 9 (equation 1) x + 2y = 13 (equation 2) multiply equation 1 by (-1) -x - 2y = -9 x + 2y = 13 add the equations together 0 + 0 = 4 0 = 4 since the equations dont equal out then these equations do not intersect and are therefore parallel. PARALLEL is your answer
x=4 y=0
10