Q: How do you graph x plus 2y-4?

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(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)

2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)

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It is not possible to draw a graph using this browser.

solve for y so if x + y = 0 then y = -x

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(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)

Set it equal to 0 and subtract x and solve for y

2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)

graph the inequality 5x+2y<4

You move the graph upwards by 2 units.

y=x+1 there for answer is 2

It is translated left 8 and up 4.

y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.

(-1,0)

If you mean: 4x -3y = 1 and x -2y = 4 then the solutions are x = -2 and y = -3

You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.

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