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How high does a ball go if it is thrown up with an initial speed of 10 meters per second?
Wiki User
∙ 14y ago
applying the equation:
(VxV) -(UXU) = 2aS
on reaching the maximum height the ball stops so the final velocity(V) becomes =0.
initial velocity as given is (U)=10 m/s.
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acceleration is here gravity in downward direction so (a)=-9.81 m/s
so applying the above stated formula the height reached by the ball(S)=5.0968 m
(approx)
Wiki User
∙ 14y ago
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