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What else can I help you with?
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second what is an equation the height in ft of the crisket as a function of time in seconds since it jumped?
4ft*Ns=H
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
Question-1 A body is thrown vertically upwards The distance st above the ground after t seconds is given by st 20t-5t2 meters?
The equation for vertical motion is y = v0t + .5at2. y is vertical displacement v0 is initial vertical velocity a is acceleration (in meters, normal gravitational acceleration is about -9.8 m/s/s, assuming positive y is upward displacement and negative y is downward displacement)
How long does it take to hit the ground from 28000 feet high?
The answer will depend on what "it" is, and on what its initial velocity is.
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
If a basketball player throws a ball from 2.0m in the air towards the hoop 10m away If the hoop is 3.05m off the ground and the initial angle is 40 degrees what is the initial velocity?
The initial velocity of the ball can be calculated using the kinematic equation for projectile motion. By using the vertical component of velocity (V0y) and the time of flight, we can determine the initial velocity needed for the ball to reach the hoop. The velocity components are V0x = V0 * cos(θ) and V0y = V0 * sin(θ), where θ is the initial angle. The time of flight in this case is determined by the vertical motion of the ball, and it can be found by using the equation of motion for the vertical direction, considering the initial vertical velocity, the gravitational acceleration, and the vertical displacement of the ball. Once these values are calculated, the initial velocity can be computed by combining the horizontal and vertical components of the motion.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
A projectile is fired horizontally from a gun that is 71.0 m above flat ground emerging from the gun with a speed of 250 ms What is the magnitude of the vertical component of its velocity as it st?
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
If a cricket jumps off the ground with an initial vertical velocity of 4 ft per second what is an equation the height in ft of the crisket as a function of time in seconds since it jumped?
4ft*Ns=H
A arrow is shot strait up at an initial velocity of 250meters per seconds How long will it take to hit the ground?
To calculate the time it takes for the arrow to hit the ground, we need to consider the vertical motion of the arrow. The time taken for an object to fall back to the ground can be determined using the kinematic equation: h = (1/2)gt^2, where h is the initial height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time. In this case, the initial velocity is upwards, so the initial height will be 0. Using the equation, we can determine the time it takes for the arrow to hit the ground.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
A ball is thrown from the ground into the air at a height of 9.1 m the velocity is observed to be v7.6i 6.1j in meters per second x axis horizontal y axis vertical and up a to what maximum h?
To find the maximum height, we first need to separate the initial velocity into its x and y components. Since the initial velocity is given as v = 7.6i + 6.1j, the initial vertical velocity is 6.1 m/s. We can use the kinematic equation for vertical motion: v_f^2 = v_i^2 + 2aΔy, where v_f = 0 at the maximum height. Rearranging the equation to solve for the maximum height, h, we have h = (v_i^2)/2g, where g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we find h ≈ 1.88 m.
If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?
To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.
When you jump upward your hang time is the time your feet are off the ground Does hang time depend on your vertical component of velocity when you jump your horizontal component of velocity or both?
Hang time depends on your vertical component of velocity when you jump. The higher the vertical velocity, the longer your feet will be off the ground. The horizontal component of velocity does not affect hang time.
A base jumper jumps off of a cliff that is 200 meters high How long will is take before he hits the ground?
you need a quadratic equation for this ½ at2 + vot - s = 0 vertical acceleration (a) is gravity (-9.8ms-2) initial vertical velocity is 0 his vertical height above ground is 200 (s=200) pop all that in the equation and you're done yep... and I'm sorry but I've had to delete my quadratic formula off my calculator and I've finished maths for the year and can't be stuffed doing it by hand.. you know the quadratic formula.. have fun :)
When will a stone return to the groun if it is thrown upward with an initial velocity of 16ms?
The stone will return to the ground when its vertical velocity becomes zero and it starts to fall back down. The time it takes for this to happen can be calculated using kinematic equations. In this case, the time can be found by setting the vertical velocity to zero and solving for time.
