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What is the height of a rock that is thrown upward with an initial speed of 15 meter per second?
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
Which will hit the ground first a ball thrown horizontally at 2 meters per second off a building 20 m high or a ball dropped by a hand at the same height?
They should reach the ground together, since their initial vertical speed is the same, namely zero.
If an object is thrown upward with an initial velocity of 32 feet per second from 40 feet above the ground write the height equation?
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
A ball is thrown downward at a speed of 40 meters per second from an altitude of 781 meters Approximately how long does it take to reach the ground?
At the time the ball is thrown, which is "time 0" the downward speed is 40 m/s.Each second, the downward speed will increase by 9.8 m/s.1. Work out the speed at the end of the first second. This will be 49.8 m/s.2. Then work out how many meters it would have gone in the first second.3. Now work out the ball's height. This is the height at "time 1".4. Draw the ball at time 0 and time 1 on a sheet of paper to help you think.Now, repeat steps 1-4 until the ball's height is close to 0 or goes past 0. Your current "time X" will tell you how many seconds went by for it to get that far.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
When will an object land if it is thrown straight from a building at 5 meters per second?
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
What is the height of a rock that is thrown upward with an initial speed of 15 meter per second?
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
Which will hit the ground first a ball thrown horizontally at 2 meters per second off a building 20 m high or a ball dropped by a hand at the same height?
They should reach the ground together, since their initial vertical speed is the same, namely zero.
When a ball of mass is thrown from a height of 7 meters it rebounds to 5 meters What is the height of the ball the instant it rebounds?
The height of the ball when it rebounds is 5 meters, as given in the question.
If an object is thrown upward with an initial velocity of 32 feet per second from 40 feet above the ground write the height equation?
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
A ball is thrown downward at a speed of 40 meters per second from an altitude of 781 meters Approximately how long does it take to reach the ground?
At the time the ball is thrown, which is "time 0" the downward speed is 40 m/s.Each second, the downward speed will increase by 9.8 m/s.1. Work out the speed at the end of the first second. This will be 49.8 m/s.2. Then work out how many meters it would have gone in the first second.3. Now work out the ball's height. This is the height at "time 1".4. Draw the ball at time 0 and time 1 on a sheet of paper to help you think.Now, repeat steps 1-4 until the ball's height is close to 0 or goes past 0. Your current "time X" will tell you how many seconds went by for it to get that far.
How long does it take for a ball to hit the ground if it was thrown vertically atop a 2 meter building at 15 meters per second vertically?
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
A ball is thrown horizontally from a cliff at a speed of 15 and strikes the ground 45 meters from the base of the cliff How high was the cliff?
Using the horizontal distance and horizontal velocity of the ball, you can calculate the time it took for the ball to reach the ground. Then, you can use the time and the vertical acceleration due to gravity to find the height of the cliff using the equation: height = (1/2) * gravity * time^2. In this case, the height of the cliff would be approximately 11.3 meters.
A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff?
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
The height h of a ball thrown into the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation?
At any time 't' seconds after the ball is released,until it hits the ground,h = 5 + 48 t - 16.1 t2
If a ball is thrown at an angle of 40 degrees above the horizontal at a speed of 16 meters per second from the top of a 12.4 m tall building what is the maximum height of the ball above the ground?
The maximum height of the ball above the ground can be calculated using the vertical component of the initial velocity. Assuming no air resistance, the formula to determine maximum height is h = (v^2 sin^2(theta)) / (2g), where v is the initial velocity (16 m/s), theta is the angle (40 degrees), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, you can find that the maximum height of the ball is approximately 14.1 meters.
