0.0496, of course
move decimal place 2 places to left; that is what this statement means.
It is: 2*2*2*2*31 = 496
2 x 2 x 2 x 2 x 31 = 496
The positive integer factors of 496 are:1, 2, 4, 8, 16, 31, 62, 124, 248, 496The factors of 496 are: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496.
496 has two prime factors, but no prime factor pair. 2 x 2 x 2 x 2 x 31 = 496
divide by 2 then divide every answer by 2 That will give you 496, 248, 124, 62 and 31. The other 4 are 2, 4, 8 and 16.
The numbers are 31 and 32.
The factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, 248, and 496.
The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
No, 496 is a "perfect" number, the sum of all of the numbers that can be divided into it, excluding 496 itself. So 1+2+4+8+16+31+62+124+248 = 496.
It is the (-2) power.
1, 2, 4, 8, 16, 31, 62, 124, 248, and 496
Yes. 2^10 = 1024 10^2 = 100 1024 > 100 → 2^10 > 10^2