0.0496, of course
move decimal place 2 places to left; that is what this statement means.
It is: 2*2*2*2*31 = 496
2 x 2 x 2 x 2 x 31 = 496
The positive integer factors of 496 are:1, 2, 4, 8, 16, 31, 62, 124, 248, 496The factors of 496 are: 1, 2, 4, 8, 16, 31, 62, 124, 248, 496.
divide by 2 then divide every answer by 2 That will give you 496, 248, 124, 62 and 31. The other 4 are 2, 4, 8 and 16.
496 has two prime factors, but no prime factor pair. 2 x 2 x 2 x 2 x 31 = 496
The numbers are 31 and 32.
The factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, 248, and 496.
The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
It is the (-2) power.
No, 496 is a "perfect" number, the sum of all of the numbers that can be divided into it, excluding 496 itself. So 1+2+4+8+16+31+62+124+248 = 496.
Yes. 2^10 = 1024 10^2 = 100 1024 > 100 → 2^10 > 10^2
1, 2, 4, 8, 16, 31, 62, 124, 248, and 496