Using Pythagoras' theorem it is 26 feet
The language of the question is too ambiguous. In mathematics, we use precise language to avoid this problem. point a is 40 metres from the base of building B the angle of elevation to the top of building C is 51 degree and to the top of the flagpole D on top of building is 56 dedree
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CAT6a
x2 = 1.22+ 32 x2 = 1.44+ 9 x2 = 10.44 x = √10.44 x = 3.23m This is the answer.
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shoes
Assuming that the Anchor base and the antenna base are at the same elevation, then you can solve for a simple right triangle. a^2 + b^2 =c^2 Solving this gives 100.5 feet... plus whatever is required for the end wraps and cable clamping.
Assuming that the Anchor base and the antenna base are at the same elevation, then you can solve for a simple right triangle. a^2 + b^2 =c^2 Solving this gives 100.5 feet... plus whatever is required for the end wraps and cable clamping.
40
An anchor windlass, or a very large capstan with a catspaw at the base.
This shape is a right triangle, who's equation is: c2=a2+b2 In this example, c is decribed by the 50ft cable and either a or b is described by the 15 ft anchor point. So the equation becomes: 502=152+b2. Solve for b, you get sqrt(2275) which is approx 47.7 ft
square the base frame and make sure base pieces are laid straight
The language of the question is too ambiguous. In mathematics, we use precise language to avoid this problem. point a is 40 metres from the base of building B the angle of elevation to the top of building C is 51 degree and to the top of the flagpole D on top of building is 56 dedree
This is your math problem that you are supposed to solve! You are supposed to use the formula, the square of the hypotenuse is equal to the sums of the squares of the other two sides. What is your hypotenuse? It is the 32 meter long rope. Then the distance from the flagpole to the end of the rope is 12 meters. So if you take the 32 meter hypotenuse and square it. And then you can take the 12 and square it. Then you can subtract the length of the end of the rope out from the flag pole squared from the length of the rope or hypotenuse squared and have the length of the flagpole squared. Now do your math.
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66
the cordae tendinae are what anchor the atrioventricular valves to the heart