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What is the circumradius of an isosceles triangle?
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
How do you find the hypoteneuse of an isosceles right triangle?
It is very unlikely for a right angle triangle to be isosceles, however it is possible if the angles are 90, 45, and 45 degrees. It does not matter if the triangle is isosceles, this method works for all right triangles. The following formula is your answer, when h=hypotenuse, and a and b are other two sides. a2 + b2 = h2
What shape starts with the letter I?
Isosceles triangle.One option is an isosceles triangle.After 'H'? If you mean i, that would be isosceles triangle. If you really meant 'H', then hexagon would work.
What is hypotenuse in an isosceles triangle?
Only a right triangle has a hypotenuse. An isosceles triangle can be a right triangle but it doesn't have to be. If it's not, then it doesn't have a hypotenuse.
What is the center of mass vertically for an isosceles triangle with base b and height h?
2/3 * h
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
How do you find the height of an isosceles triangle if its length is 12m and base 10m?
In a isosceles triangle, the altitude is also a median. If we draw the altitude, then two congruent right triangles are formed, with hypotenuse length of 12m and base length 5 m (10/2). So the length of hypotenuse, by the Pythagorean theorem is h^2 = 12^2 - 5^2 h = √(144 - 25) h = √119 h ≈ 10.9
In an isosceles triangle if the base is 8 inches long and the legs are 10 inches long what is the measure of a base angle?
Divide the triangle in half to get 2 right-angle triangles. Then, cos (base angle). cos = 1/2 (b/h * 10) cos = 1/2 (8/10 * 10) cos = 4/10, cos = 66.42 degrees, which simplifies to 66 degrees.
What is the sides of an isosceles right triangle if the area is 144cm?
An isosceles right triangle is a 90 degree triangle that the two non-hypotenuse sides are equal. http://mathworld.wolfram.com/IsoscelesRightTriangle.html Area of a triangle is 1/2 x b x h Area of an isosceles right triangle is 1/2 b2 144 cm2 = 1/2 b2 2 (144 cm2) = 2(1/2 b2) 288 cm2 =b2 16.97 cm = b So the base and height each equal 16.97 cm The hypotenuse can be solved by the Pythagorean Theorem a2 + b2 = c2 288 + 288 = c2 576 = c2 (576).5 = (c2).5 24 = c So the sides of an isosceles right triangle with the area of 144 cm2 are 16.97 cm, 16.97 cm, and 24 cm.
How do you find the length of the legs of an isosceles right triangle when you have the hypotenuse?
Suppose the lengths of the legs is L metres and the hypotenuse is H metres. Then, by Pythagoras, L2 + L2 = H2 that is, 2L2 = H2 Or L2 = H2/2 so that L = H/sqrt(2)
How can you construct an isosceles triangle if only given the base and the vertical angle and the base angles can not be used for construction?
The answer depends on the level of your knowledge. Suppose the base is of length b and the vertical angle is x degrees. Draw the base, AC, and its perpendicular bisector. Calculate h = b/[2*tan(x/2)]. That is the height of the triangle so mark this point, B, on the perpendicular bisector. Draw AB and BC. Done!
When the vertex angle and the base of an isosceles triangle are given how do you find its area?
Let's A and x represent the given vertex angle and the base, respectively.Use the law of cosine to find the length of the legs of the triangle by doing x2 = m2 + n2 - 2mncos A, where m and n are the legs. Since the triangle is isosceles, m = n and therefore x2 = 2m2 - 2m2cos A. Solving for m gives m = sqrt(x2/(2 - cos A))Get the height of the triangle by using Pythagorean theorem. m2 = x2 + h2, where h is the height.Finally, get the area using the formula for a triangle's area, which is (base * height) / 2.
