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Assuming you are using combinations in the colloquial way (which is the mathematical "permutations" where order of selection does matter) to create a 3 digit number that does not start with 0, ie creating a number that is between 100 and 999 inclusive then:
If repeats are not allowed there are 3 × 3 × 2 = 18 possible numbers
If repeats are allowed, then there are 3 × 4 × 4 = 48 possible numbers.
If you are using combinations in the mathematical sense where order of selection does not matter and are creating groups of 3 digits, then:
If repeats are not allowed there are 4 possible groups
If repeats are allowed there are 20 possible groups.
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∙ 8y ago
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How many two digit number combinations can you get using the number 1234 without repeating a digit?
There are twelve possible solutions using the rule you stated.
If using numbers 1 - 9 how many two digit combinations can be found?
-8
How many different combinations of an 8 digit password using the same 8 digits?
1
How many 4 digit combinations using 0-9 if each number may be used more than once?
10,000 combinations.
How many 6 digit combinations from a 49 digit universe will contain a particular 3 digit combination?
There are 15180 combinations.
How many 10-digit numbers can be formed using the digits 1and 2?
You have 2 options for the first digit, 2 options for the second digit, etc. ... In total, that gives you 210 combinations.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 4 digit combinations using 123456?
216
How many 4 digit combanations using the numbers 1-7?
There are 840 4-digit combinations without repeating any digit in the combinations.
How many possible 4 digit combinations are there using 0-9 with no duplicates?
There are 5,040 combinations.
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many possible 4 digit combinations are there using 0-9. how many different combination codes are possible?
There are 210 4 digit combinations and 5040 different 4 digit codes.
How many combinations of 2 and 3 digit number using 4 and 8?
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
How many three digit combinations can be formed using 123456?
Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216
How many two digit number combinations can you get using the number 1234 without repeating a digit?
There are twelve possible solutions using the rule you stated.
How many different combinations are possible using a 6 digit code?
if its not alphanumeric, 999999 variations
If using numbers 1 - 9 how many two digit combinations can be found?
-8
