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The first digit can be 7, 6, or 5 . . . . 3 choices. For each one . . .

The second digit can be 7, 6, 5, or 0 . . . . 4 choices. For each one . . .

The third digit can be 7, 6, 5, or 0 . . . . 4 choices.

The total number of possibilities is (3 x 4 x 4) = 48

If it's OK to have '0' as the first digit, then there are 64 possibilities.

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Q: How many 3 digits number can be form from 7650 if repetition is allowed show the solution?
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