The first digit can be 7, 6, or 5 . . . . 3 choices. For each one . . .
The second digit can be 7, 6, 5, or 0 . . . . 4 choices. For each one . . .
The third digit can be 7, 6, 5, or 0 . . . . 4 choices.
The total number of possibilities is (3 x 4 x 4) = 48
If it's OK to have '0' as the first digit, then there are 64 possibilities.
It is 10000.
repetition
There are 2000 such numbers.
10 30 80
7432
It is 10000.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
Just six numbers... 345, 354, 435, 453, 534 & 543
repetition
There are 2000 such numbers.
There are 2000 such numbers.
10 30 80
Since there are only 3 digits available, repetition must be allowed. In that case, there are 30 combinations.
33 = 27 with repetition, 3! = 3*2*1 = 6 without repetition.
7432
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.