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How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many five digits numbers can be formed using 01234 without repetition assuming that number cannot begin with 0?
There are 4*4*3*2*1 = 96 such numbers.
How many 3 digit numbers can be formed from the digits 24578 if no digits can be repeated?
Oh, dude, let me break it down for you. So, you've got 5 digits to choose from for the hundreds place, then 4 left for the tens place after you've used one for the hundreds, and finally 3 left for the units place after using 2 for the hundreds and tens. Multiply those together and you get 60 possible 3-digit numbers. Easy peasy, lemon squeezy!
How many different 3 digit number can be formed from 13579 if there's repetition?
As there are 5 different digits, allowing for repetition of a digit, the first digit can be any of the 5, and for each of these, the second can be any of the 5, and so for the third, making: 5 x 5 x 5 = 125 different 3-digit numbers.
How many 3 digits combinations can be made from 1234567890?
To calculate the number of 3-digit combinations that can be made from the numbers 1-9, we can use the formula for permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the total number of options (10 in this case) and r is the number of digits in each combination (3 in this case). Therefore, the total number of 3-digit combinations that can be made from the numbers 1-9 is 10^3 = 1000.
How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?
There are 2000 such numbers.
How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?
There are 2000 such numbers.
How many 5 digit numbers can be made using the digits 12679 if repetition isn't allowed?
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
What is the smallest five digit number you can form with the digits 0 1 2 3 and 4 if repetition of digits is allowed?
It is 10000.
How many 9 digit numbers which are divisible by 4 can be formed by using the digits 1 to 5 if repetition of digits is not allowed?
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
What is this called when the digits in the number repeat?
repetition
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many number combinations can you make with the numbers 1234567890?
The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.
What is the number of four digit numbers which can be formed using four of the digits 0 1 2 3 and 4 without repetition?
1
How many 4 digits can be formed with 123578 if there is no repetition?
The number of different 4-digit strings is 6*5*4*3 = 360
How many 5 digit numbers can be formed using the digits 0 1 2 3 4 5 6 7 8 9 if no repetition is allowed?
If the first number can not be zero then it is 9x9x8x7x6=27,216 If the first number can be zero then it would be 10x9x8x7x6=41,160
