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How many 3 number combinations can you make from 1 2 3 4 5 using each number once?
Wiki User
∙ 13y ago
123, 124, 125, 132, 134, 135, 142, 143, 145, 152, 153, 154
213, 214, 215, 231, 234, 235, 241, 243, 245, 251, 253, 254
312, 314, 315, 321, 324, 325, 341, 342, 345, 351, 352, 354
412, 413, 415, 421, 423, 425, 431, 432, 435, 451, 452, 453
512, 513, 514, 521, 523, 524, 531, 532, 534, 541, 542, 543
A total of sixty combinations.
You could also use the Permutation formula with no repetition to get the result, without having to list them all out. This is important once you start getting into higher numbers.
The formula is n! / (n-r)! where n is the total number of items, and r is the number of items you are taking for each permutation.
The exclamation (!) means factorial. You take n * (n-1) * (n-2) * (n-3) * . . . . * 1.
In this case n=5 and r=3
so 5! / (5-3)! = (5 * 4 * 3 * 2 * 1) / (2 * 1) = 120/2 = 60. I'm posting a link for more information.
Wiki User
∙ 13y ago
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How many 3 numbers combinations can you make from 1 3 7 using each number once?
137, 173, 317, 371, 713, 731 Six combinations can be made.
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35
How many symbols can you make with a 7 LED grid?
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
How many 3 number combinations can you make using the numbers 1-45?
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
How many 6 numbers combinations can you make from 1 2 3 4 5 6 and you can use multiple combinations but still use each number only once?
720
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How many combinations can you make with 2 letters?
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How many combinations of 3 things can you make using 4 choices for each thing?
4
How many combinations can you make using numbers 1 through to 10 each with three different numbers?
1000
How many 5 numbers combinations can you make from numbers 1 through 35 and you can use multiple combinations but still use each number only once?
35
How many combinations can you make using 1-8?
9
How many symbols can you make with a 7 LED grid?
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
How many 3 number combinations can you make using the numbers 1-45?
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
How many 6 numbers combinations can you make from 1 2 3 4 5 6 and you can use multiple combinations but still use each number only once?
720
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
What are the 100000 number combinations you can make using 0 - 9?
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.
