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To calculate the number of 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each, we can use the permutation formula. There are 4 choices for the first digit, 3 choices for the second digit, 2 choices for the third digit, and 1 choice for the fourth digit. Therefore, the total number of combinations is 4 x 3 x 2 x 1 = 24. So, there are 24 possible 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each.
To calculate the number of 4-number combinations using the numbers 1, 2, 3, 4, and 5 without repetition, you can use the formula for permutations. Since order matters in a combination, you would use the formula for permutations, which is nPr = n! / (n - r)!. In this case, you would have 5 choices for the first number, 4 choices for the second number, 3 choices for the third number, and 2 choices for the fourth number. Therefore, the total number of 4-number combinations would be 5P4 = 5! / (5-4)! = 5 x 4 x 3 x 2 = 120 combinations.
There are 5 choices for the first letter, 4 choices for the second letter, 3 choices for the third letter, 2 choices for the fourth letter, and 1 choice for the fifth letter. Therefore, the total number of 5-letter combinations that can be made using the letters a, b, c, d, and e is 5 x 4 x 3 x 2 x 1 = 120. Some examples of these combinations include abced, acbde, and eadbc.
To calculate the total number of possible 4-digit combinations using the digits 0-9, we can use the fundamental counting principle. Since there are 10 options (0-9) for each digit in the combination, there are 10 choices for the first digit, 10 choices for the second digit, 10 choices for the third digit, and 10 choices for the fourth digit. Multiplying these choices together gives us a total of 10 x 10 x 10 x 10 = 10,000 possible 4-digit combinations using the digits 0-9.
3,124,550 possible combinations