There are 900 possible combinations, starting with 1005....
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If the digits can't repeat . . .
The first can be 1, 2, 3, 4, 6, 7, 8, or 9 . . . 8 choices. For each one . . .
The second can't be 5 or the one used . . . 8 choices. For each one . . .
The third can't be 5 or the two used . . . . . 7 choices. For each one . . .
The fourth one is 5.
Total number of possibilities = (8 x 8 x 7 x 1) = 448.
If the digits can repeat:
The first can be any one of 9 choices (all except zero). For each one . . .
The second can be any of 10 choices. For each one . . .
The third can be any one of 10 choices. For each one . . .
The fourth is 5.
Total number of possibilities = (9 x 10 x 10 x 1) = 900.
There are 360 of them.
There are twelve possible solutions using the rule you stated.
10,000 combinations.
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
There are 59049 combinations, all the way from 11111, 11112 through 99998, 99999. There are too many to list here.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
There are 360 of them.
There are twelve possible solutions using the rule you stated.
There are 9999 possible combinations starting from 0000 to 9999
The number of combinations is the number of characters - in this case, 10 - raised to the power if the number of places. So using only the numerals zero through nine, and a 10-character PIN, there are 10 raised to the tenth power combinations, or 1,000,000,000 different possibilities.
10,000 combinations.
It is: 9C7 = 36
66
15
10,000
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.